Consider a population of size N = 100 with the three individual mutants with relative growth rate rA = 2, rB = 1.01, and rC = 0.99. What is the probability that each of the three mutants will take over the population?

Answer 1 / 25

Step-by-step explanation:

The probability that the first

of the three mutants will take over the population = 2 / 100

The probability that the second

of the three mutants will take over the population = 1.01 / 100

The probability that the third

of the three mutants will take over the population = 0.99 / 100

Therefore, the probability that each of the three mutants will take over the population = probability of the first,second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99)/100 = 4 / 100 = 2/25

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: