The population of locusts in a certain swarm doubles every two hours. If 4 hours ago the swarm just doubled to 1,000 locusts, in approximately how many hours will the swarm population exceed 250,000 locusts?

14 hours

Step-by-step explanation:

The population of locusts in a certain swarm doubles every two hours.

If 4 hours ago the swarm just doubled to 1,000 locusts.

The population now will be 1000X2X2=4000

This is an example of a geometric progression with

First term, a=4000

Common ration, r=2

We want to determine in how many hours, the population will exceed 250,000.

Nth term of a G.P.

Uₙ=arⁿ⁻¹

arⁿ⁻¹>250000

4000 X 2ⁿ⁻¹ >250000

2ⁿ⁻¹ > 2⁶ > 62.5

n-1>6

n>7

Since an increase occurs every 2 hours, It means that in approximately 14 hours, the population will increase to over 250000.

idk

step-by-step explanation:

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,