Let ˆθ be a statistic that is normally distributed with mean θ and standard error σθˆ. Show that 100(1 − α)% confidence interval for θ is given by: ˆθ ± z α 2 σθˆ

Step-by-step explanation:

We are given the following in the question:

is distributed normally.

Mean =

Standard error =

Significance level =

Thus, the confidence percentage is

Confidence interval:

Putting the values, we get,

which is the required confidence interval.

d

step-by-step explanation:

in a an geometric explicit equation, the first number is the starting rate. in this case 10.