Using the prostate data from the faraway package with lpsa (log prostate specific antigen) as response and lcavol (log cancer volume) as predictor, the fitted model is lpsa = 1.507 + 0.719 lcavol. Provide an interpretation of the estimated coefficient for lcavol based on the fact that both variables are log-transformed.

Step-by-step explanation:

Given that,pros.

lpsa = 1.507 + 0.719 lcavol

lpsa=0.719 lcavol + 1.507

Comparing this to equation of a straight line, y=mx+c

Then,

slope (m) = 0.719

And intercept (c) on y axis is 1.507

Then, the x axis is lcavol

Also, the y axis is lpsa.

Then the linear model preview is

Check attachment for the preview.

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step-by-step explanation: