What does the converse of the Pythagorean Theorem say about a triangle with sides of length a, b, and c, where c>a and c>b?

A. If it is a right triangle, then a2+b2=c2.

B. If a2+b2=c2, then it is a right triangle.

C. If it is not a right triangle, then a2+b2≠c2.

D. If a2+b2≠c2, then it is not a right triangle.

The converse of the Pythagorean Theorem is: If the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle. That is, in ΔABC, if c2=a2+b2 then ∠C is a right triangle, ΔPQR being the right angle.

16 minutes is correct

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

when multiplying or dividing by a negative on both sides you have to flip the inequality sign. this rule only applies to multiplying or dividing by a negative number in inequality equations. this rule is really important.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice