Find the equation of the line passing
through the points (3,-2) and (4, 6).
y = 8x + [?]

y+2=8(x-3)

Step-by-step explanation:

m= (y2-y1)/(x2-x1)

m=(6-(-2))/(4-3)

m=(6+2)/(1)

m=8

8 is your slope. now chose any point that is given to you. fr example you can chose from (3,-2) or (4,6).

i'll chose first one (3,-2) and plug in the equation.

(y-y1)=m(x-x1)

y and x doesn't changes it stay the same. but for y1 and x1 you can plug the point you decided to use. me (3,-2)

y+2=8(x-3)

if you want me to do for the second point you can ask for it..

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .