Two sides of a triangle have lengths of 12m and 15m. The angle between them is increasing at a rate of 0.06 rad/s. Find the rate at which the area of the triangle is increasing

Step-by-step explanation:

Area of a triangle = 1/2 × b × h

= 1/2 × b × l × sin theta

Given:

b = 15m

l = 12m

Dtheta/dt = 0.06 rad/s

Area = 1/2 × 15 × 12 × sin theta

= 90 × sin theta

dA/dt = dA/dtheta × dtheta/dt

= 90 cos theta × 0.06

Including pythagoras rule,

Cos pi/3 = 1/2

= 90 × 1/2 × 0.06

= 2.7 m2/s

is there a picture

step-by-step explanation:

probably .5

i can on others if necessary.