Suppose that the probability of suffering a side effect from acertain flu vaccine is 0.005. If 1000 persons are inculated, findapproximately the probability that:

a) At most 1 person suffers
b) 4,5,or 6 persons suffer

The answers to the question are

a) The probability that at most 1 person suffers side effect from the flu vaccine is 4.043×10⁻²

b) The probability that 4,5,or 6 persons suffer side effect from the flu vaccine is 0.49716.

Step-by-step explanation:

We solve the question using the formula for Poisson probability as follows

Let the probability of suffering a side effect from a certain flu vaccine be p

we have n = 1000 and p = 0.005

then by binomial theorem μ = 1000*0.005 = 5

using  Poisson probability formula, we have

where λ = μ

for P(X=0) we have 6.73×10⁻³

P(X=1) we have 3.37×10⁻²

Using the addition rule, we have

P (X≤1) = P(X=0) + P(X=1) =  6.73×10⁻³ + 3.37×10⁻² = 4.043×10⁻²

b) Similarly, we have for k = 4, 5, 6 we have

P(X=4) we have 0.1755

P(X=5) we have 0.1755

P(X=6) we have 0.14622

Therefore P(X=4) or P(X=5), P(X=6)  is given by

0.1755 + 0.17546 + 0.14622 = 0.49716

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632