Two points of a triangle are located at (0, 0) (4, 0) . Which two of the following correctly describe where a third point can be placed so that the area of the triangle is 4 square units?

A. anywhere along the graph of x = 2
B. anywhere along the graph of x = 4
C. anywhere along the graph of y = - 2
D. anywhere along the graph of y = 2
E. anywhere along the x-axis F. anywhere along the y- axis

Tell me how you got the it use the figures to answer questions 1and 2. in each diagram, line k is parallel to line l, and line t intersects lines. 1. based on the diagrams, what is the value of x? 2. how would you verify your answer for x?

Solve the system by the elimination method. x + y - 6 = 0 x - y - 8 = 0 when you eliminate y , what is the resulting equation? 2x = -14 2x = 14 -2x = 14

Sample response: if the graph passes the horizontaline test, then the function is one to one. functions that are one to one have inverses that a therefore, the inverse is a hinction compare your response to the sample response above. what did you include in your explanation? a reference to the horizontal-line test d a statement that the function is one-to-one the conclusion that the inverse is a function done