If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (f circle g) (x)?
(3x + 2)(x 2 + 1)
3x 2 + 1 + 2
(3x + 2)2 + 1
3(x 2 + 1) + 2

(3x+2)^2+1

Step-by-step explanation:

(f°g)(x) =g(f(x)) =g(3x+2)=(3x+2)^2 +1

Choice D,  3 (x^2+1) + 2

Explenation:

f(g(x)) = f (x^2 + 1) = 3 * (x^2 +1) + 2 = (3 x^2 + 3) + 2                  

Factor 3 from each term:

(x^2 _1) + 2

which makes the answer choice "d".

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

f

step-by-step explanation:

f