If triangle ABC is a right triangle and BC is a semicircle, find the total area of the figure below. what is the diameter of the semi-circle? units.
Area= units squared (rounded to the nearest hundredth. )
side AB is 3 units long.
Side AC is 4 units long.

Area of the semi-circle = 9.8125 square units

Solution:

Given ABC is a right triangle.

BC is a semi-circle.

∠BAC = 90°.

AB = 3 units and AC = 4 units.

BC is the hypotenuse of the right triangle ABC.

Using Pythagoras theorem,

In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.

Take square root on both sides.

BC = 5 units

The diameter of the semi-circle is 5 units.

Radius = 5 ÷ 2 = 2.5 units

Area of the semi-circle =

                                      = 9.8125 square units

Area of the semi-circle = 9.8125 square units

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: