A man bought two radio sets for Rs 5000 . He sold one at a loss of 12% and the other at gain of 8% . He neither gained nor loss in the transaction . Find the cost price of each radio

2000 radios were sold at a 12℅.

3000 radio were sold at a 8%

Step-by-step explanation:

Let x represent the cost of the radio8% loss that was sold at a loss of 12%.

Let y represent the cost of the radio that was sold at a gain of 8%.

A man bought two radio sets for Rs 5000 . He sold one at a loss of 12% and the other at gain of 8%. This means that

x + y = 5000

Profit made on the first radio is 0.12x

Profit made on the second radio is 0.08x.

He neither gained nor loss in the transaction. This means that

0.12x = 0.08y - - - - - - - - - -- - -1

Substituting x = 5000 - y into equation 1, it becomes

0.12(5000 - y) = 0.08y

600 - 0.12y = 0.08y

0.08y + 0.12y = 600

0.2y = 600

y = 600/0.2

y = 3000

x = 5000 - y = 5000 - 3000

x = 2000

according to egenuity the answer is

step-by-step explanation:

d. 344.22

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.