PLEASE SOMEONE HELP AND SHOW UR WORK..
A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round your answer to the nearest tenth of a cubic cm. Use 3.14 to approximate pi, and make certain to show your work. Hint: you may need to find the volume of the component shapes.

The answer is 2,713 in³

The volume (V) of the prop is the sum of the volume of cone (V1) and half of the volume of the sphere (V2): V = V1 + 1/2 * V2

Volume of the cone is:

V1 = π r² h / 3

According to the image,

h = 14 in

r = 9 in

and

π = 3.14

V1 = 3.14 * 9² * 14 / 3 =  1,186.92 in³

The volume of the sphere is:

V2 = π r³ * 4/3

According to the image,

r = 9 in

and

π = 3.14

V2 = 3.14 * 9³ * 4/3 = 3,052.08 in³

The volume of the prop is:

V = V1 + 1/2 * V2

V = 1,186.92 in³ + 1/2 * 3,052.08 in³

V = 1,186.92 in³  + 1,526.04 in³ 

V = 2,712.96 in³ ≈ 2,713 in³

idk

step-by-step explanation:

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12