It is desired to determine whether there is less variability in the silver plating done by Company 1 than in that done by Company 2. If independent random samples of size 12 of the two companies' work yield s1 = 0.035 mil and s2=0.062 mil, test the null hypothesis sigma12 = sigma22 against the alternative hypothesis sigma12 < sigma22 at the 0.05 level of significance. The F statistic for this test is . The decision is to, at alpha = 0.05, reject H0.

The conclusion is that the data provides evidence to believe that the plating done by Company 1 is less variable than that done by Company 2. Enter 0 if this statement is FALSE or 1 otherwise .

The conclusion is True

Step-by-step explanation:

Solution:

- The standard deviation of company s1 = 0.035

- The standard deviation of company s2 = 0.062

- Null Hypothesis : s1^2 = s2^2

- Alternate hypothesis : s1^2 < s2^2

- Criteria to reject Null: M > M_a ( 12 - 1 , 12 - 1 )

- From Tables,  M > 2.82

- M - statistics value M = s2^2 / s1^2

- M = (0.062 / 0.035)^2 = 3.14

- M = 3.14 > 2.82 ... Criteria of rejection is met

- Null Hypothesis must be rejected at level of significance a = 0.05

- p value, 1 - 0.965 = 0.035 < 0.05 ( Significance Level )

- The conclusion is True

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.