Mathematics, 11.03.2020 04:39 gatorboy1788

Before 1918, approximately 55% of the wolves in a region were male, and 45% were female. However, cattle ranchers in this area have made a determined effort to exterminate wolves. From 1918 to the present, approximately 65% of wolves in the region are male, and 35% are female. Biologists suspect that male wolves are more likely than females to return to an area where the population has been greatly reduced. (Round your answers to three decimal places.)

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Answer from: irisprats

(a) 0.1911

(b) 0.0610

(d) 0.6683

Step-by-step explanation:

Let p = 0.55, q = 1 - 0.55 = 0.45, n = 11

(a) the required Probability is Pr(X> or = 8)

PR(X>=8) = Pr(X= 8)+ Pr(X=9) +Pr( 10) + Pr(11)

Pr(X>= 8) = 11C8(.55)^8(0.45)³ + 11C9(0.55)^9(0.45)² + 11C10(0.55)^10(0.45) + (0.55)^11

P(X>= 8) = 0.1259 + 0.0513 + 0.0125 + 0.00139

~= 0.1911

(b) p = 0.45, q = 0.55

Pr(X>= 8) = 11C8 × (.45)^8 × (0.55)³ + 11C9 × (0.45)^9 × (0.55)² + 11C10 × (0.45)^10 × (0.55) + (0.45)^11

P(X>= 8) =0.04616 + 0.01259 +0.002060 + 0.000153

~= 0.0610

(c )the required probability is Pr( X<5).

Where p= 0.45, q = 0.55

Pr(X<5) = Pr(X= 4)+ Pr(X=3) +Pr(=2) + Pr(=1) + P(X=0)

Pr(X<5) = 11C4 × (0.45)⁴× (0.55)^7 + 11C3 ×(0.45)³ × (0.55)^8 + 11C2 × (0.45)² ×(0.55)^9 +11C1 × (0.45)(0.55)^10 + 11C0 × (0.55)^11

= 0.2060 + 0.1259 + 0.0513 + 0.0125 + 0.0014

= 0.3971

The required probability that 8 or more were male

PR(X>=8) = Pr(X= 8)+ Pr(X=9) +Pr( 10) + Pr(11)

Pr(X>= 8) = 11C8 × (.65)^8 × (0.35)³ + 11C9 × (0.65)^9 × (0.35)² + 11C10 × (0.65)^10 × (0.35) + (0.65)^11

P(X>= 8) = 0.2254 + 0.1395 + 0.05183 + 0.00875

= 0.4255

(d) The required probability that 8 or more were female is given by

p = 0.35, q= 0.65

PR(X>=8) = Pr(X= 8)+ Pr(X=9) +Pr( 10) + Pr(11)

Pr(X>= 8) = 11C8 × (.35)^8 × (0.65)³ + 11C9 × (0.35)^9 × (0.65)² + 11C10 × (0.35)^10 × (0.65) + (0.35)^11

P(X>= 8) = 0.0102 + 0.00183+ 0.000197 +0.00000965

= 0.0129

(e) (b )the required probability is Pr( X<5).

p =0.35, q = 0.65

Pr(X<5) = Pr(X= 4)+ Pr(X=3) +Pr(=2) + Pr(=1) + P(X=0)

Pr(X<5) = 11C4 × (0.35)⁴× (0.65)^7 + 11C3 ×(0.35)³ × (0.65)^8 + 11C2 × (0.35)² ×(0.65)^9 +11C1 × (0.35)(0.65)^10 + 11C0 × (0.65)^11

= 0.2428 + 0.2254 + 0.1395 + 0.05183 + 0.00875

= 0.6683

Answer from: Quest

Where's the rest of the

Answer from: Quest

25.3

step-by-step explanation:

1st step

add 3+6

multipy 9*3

=37

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Before 1918, approximately 55% of the wolves in a region were male, and 45% were female. However, ca...

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