Chauncey Billups, a current shooting guard for the Los Angeles Clippers, has a career free-throw percentage of 89.4%. Suppose he shoots six free throws in tonight’s game. What is the standard deviation of the number of free throws that Billups will make?

Step-by-step explanation:

We are given the following in the question:

We treat free throws as a success.

P(Billups make a free throw) = 89.4% = 0.894

Then the number free throw follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.

WE have to find the standard deviation of the number of free throws that Billups will make.

We are given n  = 6.

Standard deviation formula:

0.754 is the standard deviation of the number of free throws that Billups will make.

x=12 units bd= 10 units

step-by-step explanation: