Find the quotient when x2 + 10x + 21 is divided by x + 7

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Work Shown:

x^2+10x+21 factors to (x+3)(x+7) since

7+3 = 10 and 7*3 = 21

Or you can use the FOIL rule to see that (x+3)(x+7) expands to x^2+10x+21

When we divide x^2+10x+21 over x+7, we get,

a pair of (x+7) terms cancel out when we divide

The quotient is x+3

The remainder is 0

See the diagram below for the long division table

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1