The integral Integrate 9t/ 1+ 81 t^2 dt can be rewritten as Integrate t/1+81 t^2 (9/162) dt. By substituation we have Integrate w (9/162) dw = 1/8 Integrate w dw = 18 In w. Writing this in terms of t we have 18 In (1 + t^2).

step-by-step explanation:

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step-by-step explanation:

answer

a) the midrange of the data set shown is 85.5

step by step explanation

let's find the midrange.

the midrange is nothing but add the greatest value and the least value, then divide it by 2.

here the greatest value = 99

the least value = 72

midrange = (99 + 72)/2

= 171/2

midrange = 85.5

you.