Calculate the per unit active power of one-phase Pu,1 = real(V˜ as, u ˜I ∗ a, u) from the results of Problem 5. Also, calculate the per-unit three-phase powers Pu(t) = P(t)/S3b and Pu = P/S3b using the results from problem 4. Are the numerical values of the per unit powers Pu,1, Pu(t), Pu, equal or different? why?\

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

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explanation:

step-by-step explanation: