The radius of circle Ois 28, and OC = 9. The diagram is not drawn to scale. What is the length of AB? Round the answer to the nearest tenth.
58.8
53.0
29.4
26.5

53.0

Step-by-step explanation:

How we get the

the complement of the question proposed one of the choices given beneath:

a) 58.8

b) 53.0

c) 29.4

d) 26.5

as we observe at the figure, AOB an isosceles triangle, and OCB is a right triangle

consider OCB

OC =9, OB= radius = 28

the problem is how to find the length of CA, for that C is a midpoint of segment AB, so AC=BC

BC can be found by using pythagorean theorem

OB²= OC² + CB²,  this implies CB² = OB² - OC²

CB² = 28² - 9² = 784 - 81=703, therefore CB= sqrt (703)=26.51

CB=26.51, since CB= AC, so  AC=CB= 26.51

finally the the length of AB is AB = 2 x CB = 2x AC= 2x 26.51= 53.0

the answer is b) 53.0

360 different combinations

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!