The probability a person living in the U. S. has a valid U. S. passport is 0.28. The probability a person living in the U. S. is not a U. S. citizen is 0.12. Assume a person living in the U. S. with a valid U. S. passport is mutually exclusive of the person being a U. S. citizen. What is the probability a person living in the U. S. has a valid U. S. passport and is not a U. S. citizen

Step-by-step explanation:

given that the probability a person living in the U.S. has a valid U.S. passport is 0.28. The probability a person living in the U.S. is not a U.S. citizen is 0.12

Assume a person living in the U.S. with a valid U.S. passport is mutually exclusive of the person being a U.S. citizen.

P(A) = Prob ( a person has a valid US passport) = 0.28

P(B) = Prob (person living is not a US citizen) = 0.12

A and B' are disjoint.

Prob a person living in the U.S. has a valid U.S. passport and is not a U.S. citizen= P(AB) = P(A) -P(AB')

= 0.28-0

=0.28

how long did the flood last

step-by-step explanation:

then i will answer

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions