The length of a rectangle is 2 feet more than four times the width . The perimeter is 74 feet . Find the dimensions

Length is 30 feet and width is 7 feet.

Step-by-step explanation: The dimensions of the rectangle are not given, but the clues given in the question are such that, if the width is W, then the length would be two feet more than four times the width. In other words, the length would be, two plus four times the width, which can be expressed as

2 + 4W. The perimeter given as 74 feet is calculated as

Perimeter = 2(L + W)

If perimeter equals 74, length equals 2 + 4W and width equals W, then the perimeter can be expressed as

74 = 2(2 + 4W + W)

74 = 2(2 + 5W)

74 = 4 + 10W

Subtract 4 from both sides of the equation

70 = 10W

Divide both sides of the equation by 10

W = 7

Hence, if the width is 7, the length would be calculated as

Length = 2 + 4W

Length = 2 + 4(7)

Length = 2 + 28

Length = 30.

Therefore the length equals 30 feet and the width equals 7 feet.

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0