How many grams of a 10% cream must be mixed with 2% cream to prepare 60 grams of a 5% cream?

22.5 grams of 10% cream is mixed with 37.5 grams of 2 % cream to prepare 60 grams of 5% cream.

Step-by-step explanation:

Let x grams of 10% cream is mixed with y grams of 2 % cream to prepare 60 grams of 5% cream.

So, x + y = 60 ............ (1) and

⇒ 10x + 2y = 300

⇒ 5x + y = 150 ............ (2)

Now, solving equations (1) and (2) we get,

4x = 150 - 60 = 90

⇒ x = 22.5 grams

So, y = 60 - x = 37.5 grams. (Answer)

i dont know

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1