Given: UR ∥ ST ∠R, ∠T right angles Prove: ∆RSU ≅ ∆TUS

It is proved that ∆ R S U ≅ ∆ T U S

Step-by-step explanation:

Compare Δ R S U & Δ T U S

∠ R = ∠ T

Side S U is common in both triangle.

So in these two triangles one angle & one side are same, so Property of similarity of triangles is satisfied. so

∆ R S U ≅ ∆ T U S

Proved.

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.