Find the charge on the capacitor in an LRC-series circuit at t = 0.02 s when L = 0.05 h, R = 3 Ω, C = 0.02 f, E(t) = 0 V, q(0) = 7 C, and i(0) = 0 A. (Round your answer to four decimal places.) 6.39 Correct: Your answer is correct. C Determine the first time at which the charge on the capacitor is equal to zero. (Round your answer to four decimal places.) .2 Incorrect: Your answer is incorrect. s

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

college

english, cause i can’t you

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.