Carbon-14 is a radioactive element with a half-life of about 5,730 years. Carbon-14 is said to decay exponentially. The decay rate is 0.000121. We start with one gram of Carbon-14. We are interested in the time (years) it takes to decay Carbon-14. Find the amount (percent of one gram) of Carbon-14 lasting less than 5,730 years. This means, find the probability P(x < 5,730).

The percentage of Carbon-14 lasting less than 5,730 years is 50%.

Step-by-step explanation:

Let X = number of years it takes for Carbon-14 to decay.

The random variable X follows an Exponential distribution with decay parameter, λ = 0.000121.

The probability mass function of X is:

Compute the value of P (X < 5730) as follows:

The percentage of Carbon-14 lasting less than 5,730 years is,

0.5000 × 100 = 50%

Thus, the percentage of Carbon-14 lasting less than 5,730 years is 50%.

it's both, now can you answer my most recent question?

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.