Use matrix inversion to solve the collection of systems of linear equations. HINT [See Example 4.] (a) −x − 4y + 2z = −10 x + 2y − z = 11 x + y − z = 14

Step-by-step explanation:

given is a system of linear equations in 3 variables as

This can be represented in matrix form as

AX=B Or

So solution set

X would be

|A|=-1(-1)+4(0)+2(-1)=--1

Cofactors of A are

-1    0    -1

-2   -1     -3

0     1      2

So inverse of A is

1    2   0

0   1     -1  

1     3      -2

Solution set would be

x=12

y=-3

z=-5

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.