A pizza is cut into six unequal slices (each cut starts at the center). The largest slice measures $90$ degrees: [asy] unitsize(0.35inch); defaultpen(black+1); void pie(pair ctr, real fract, int slices, string lbl){ path c = circle(ctr,1); draw(c); fill(c, darkblue); path s = (ctr+(0,1)--ctr--ctr+(sin(2*pi*frac t),cos(2*pi*fract))..Ctr+(sin(pi*fr act),cos(pi*fract))..Cycle); draw(s); fill(s, yellow); for(int i=0;i

42 would be the answer for the question.

Step-by-step explanation:

This is because the degree measures are  90, 90-d, 90-2d, 90-3d, 90-4d,90-5d.

6(90)-(1+2+3+4+5)d

= 540-15d

There are 360 degrees in a pizza.

540-15d=360

Then, subtract 360 from each side

180-15d=0

Add 15d to each side.

180=15d

d=12

then you get 90,78,66,54, 42, and 30.

SO the 5th slice measures 42 degrees!

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.