A 5-m long wire with a mass of 80 g is under tension. A transverse wave for which the frequency is 800 Hz, the wavelength is 0.6 m, and the amplitude is 4.4 mm is propagating on the wire. The maximum transverse acceleration of a point on a wire is closest to

Step-by-step explanation:

Mass of the wire m = 80g = 0.08 Kg

Length of the wire l = 5 m

Linear density of wire μ = m/l = 0.08/5 = 0.016 Kg/m

Frequency n = 800 Hz

Wavelength λ = 0.6 m

Amplitude A =  4.4mm = 0.0044m

Speed of the wave v = nλ = 800*0.6 = 480 m/s

Angular speed ω = 2πn = 2π*800 = 5028.57 rad/s

Maximum transeverse acceleration a = ω^2 A = 111260.67 m/s^2

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.