Angle α lies in quadrant II , and tanα=−125 . Angle β lies in quadrant IV , and cosβ=35 .

What is the exact value of cos(α−β) ?

Step-by-step explanation:

step 1

Find cos α

we know that

we have

substitute

Remember that Angle α lies in quadrant II

so

sec α is negative

Find the value of cos α

so

step 2

Find sin α

we know that

we have

substitute

step 3

Find sin β

we know that

we have

substitute

Remember that

Angle β lies in quadrant IV

so

sin β is negative

step 4

Find cos(α−β)

we know that

we have

substitute the given values

christopher is 272,195 year old

step-by-step explanation:

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10