A poker hand consisting of 7 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactly 6 face cards. Round your answer to 4 decimal places as needed.

0.0015

Step-by-step explanation:

Ways of dealing combinations of 7 cards randomly from a randomly shuffled standard 52 card deck = 52!/(45!)(7!) = 133,784,560.

Combinations of 6 face cards from among 12 face cards = 12!/(7!)(6!) = 132. Combinations of 1 non-face cards from among (52–12)!/(38!)(1!) = 1560.

Combinations of 5 face cards and 2 non-face cards = 132×1560 = 205920

Probability as requested = 205,920/133,784,560  = 0.001539= 0.0015

jwjwkwkwkkkdjebd b jdjejdndj he jenej

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: