Agiven line has the equation 10x 2y -2.what is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12o submitted

10x + 2y = -2
2y = -10x - 2
y = (-10/2)x - 2/2
y = -5x - 1...the slope here is -5...a parallel line will have the same slope.

y = mx + b
slope(m) = -5
(0,12)...x = 0 and y = 12
now we sub...we r looking for b, the y intercept
12 = -5(0) + b
12 = b

so ur parallel line is : y = -5x + 12

Ithink it is 7. 16

The coordinates of point a right now is (-3,-1) you have to multiply these coordinates by a factor of 2 to get (-6,-2)