The number of Atlantic blue fin tuna in thousands can be modeled by P(x)=230(.881)^x where X represents the number of years since 1974. Use the model to algebraically determine the year when the Number of blue fin tuna reached 95,000

Work Shown:

Recall that P is in thousands, so P = 95 means 95,000.

Plug in P(x) = 95. Solve for x. Use logarithms to get this done.

P(x)=230(0.881)^x

95=230(0.881)^x

95/230 = (0.881)^x

0.41304347826087 = (0.881)^x

(0.881)^x = 0.41304347826087

Log( (0.881)^x )= Log( 0.41304347826087 )

x*Log( 0.881 )= Log( 0.41304347826087 )

x= Log( 0.41304347826087 )/Log( 0.881 )

x= 6.97883817154785

x= 7

Approximately 7 years after 1974 is when the population will be around 95,000.

7 years after 1974 = 1974+7 = 1981

146 days

step-by-step explanation:

1. (365*2)/5 =

730/5 =

146 days

2. 365/5=

73*2   = 146

answer: 1 + 1 = 11

step-by-step explanation: