The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation of 65 points. About what percent of students have scored between 60 and 65 points?

34%

Step-by-step explanation:

Since the points obtained by students of the class in a test are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = points obtained by students

µ = mean

σ = standard deviation

From the information given,

µ = 60 points

σ = 5 points

The probability of students that have scored between 60 and 65 points is expressed as

P(60 ≤ x ≤ 65)

For x = 60,

z = (60 - 60)/5 = 0

Looking at the normal distribution table, the probability corresponding to the z score is 0.5

For x = 65,

z = (65 - 60)/5 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.84

Therefore,

P(60 ≤ x ≤ 65) = 0.84 - 0.5 = 0.34

Therefore, the percent of students that have scored between 60 and 65 points is

0.34 × 100 = 34%

- 70

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all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: