What is the equation of a line l that has an x-intercept of (5, 0) and is perpendicular to another line m that has a slope -5?

Question 14 options:

A. y = 1/5 x + 5
B. y= -5x + 5
C. y = -5x+ 25
D. y = 1/5 x - 1

D. y = 1/5 x - 1

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

c represents the y intercept

m represents the slope of the line

The slope of the given line m is - 5

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line, I passing through (5, 0) is 1/5

To determine the y intercept, we would substitute m = 1/5, x = 5 and y = 0 into y = mx + c. It becomes

0 = 1/5 × 5 + c

0 = 1 + c

c = 0 - 1

c = - 1

The equation becomes

y = x/5 - 1

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

step-by-step explanation: