Find the mass of the solid bounded by the xy-plane, yz-plane, xz-plane, and the plane (x/2) + (y/3) + (z/6) = 1, if the density of the solid is given by δ(x, y,z) = x + y. Set up the triple integral with the order dz dy dx.

answer: f = 32.2m

step-by-step explanation: that is the answer

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

mathpapa

step-by-step explanation:

t= half of the arc subtended by t.

r= half of the arc subtended by r.  

t+r= half of the arc subtended by t + half of the arc subtended by r= half of 360=180

step-by-step explanation: