Cars arrive at a toll booth according to a Poisson process with mean 70 cars per hour. Suppose the attendant makes a phone call. How long, in seconds, can the attendant's phone call last if the probability is at least 0.5 that no cars arrive during the call

35.6 seconds

Step-by-step explanation:

The Poisson distribution has a probability model that follows the given relationship:

For x = zero calls at a probability of 50%, the arrival rate during the call is:

Since cars arrive at a rate of 70 per hour, the length of call 'n' in seconds is:

The call should be at most 35.6 seconds long to ensure a 50% probability that no cars arrive during the call.

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

5050

hope this !