Johnny has a toy tent, as seen below. The area of the base is 60 in2. The height is 8 inches. Calculate the maximum amount of water that will fill his tent.

the tent can hold 8.66 lb of water (or 240 in³ of it)

Step-by-step explanation:

assuming that the tent base is a rectangular area , and the vertical cross section is triangular , then the volume of the tent will be:

Volume of the tent = Area* height/2 = 60 in² * 8 in / 2 = 240 in³

assuming the density of water as 62.4 lb/ft³ then

mass of water = density * volume = 62.4 lb/ft³ * 240 in³ * (1 ft / 12 in)³ = 8.66 lb

then the tent can hold 8.66 lb of water (or 240 in³ of it)

step-by-step explanation:

|ab| = 1.4 = 4

h = 1.4 = 4

a(abc) area = 4.4 = 16/2 = 8

area of abc = 8 cm^2

good luck ! ; )