Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?

a No, the remainder is 0, so x-5 is not a factor of P(x)

b Yes, the remainder is 0, so x-5 is a factor of P(x)

c Yes, the remainder is -240, so x-5 is a factor of P(x)

d No, the remainder is -240, so x-5 is not a factor of P(x)

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

Step 1:  Factor

p(x) = x^3 - 5x^2 - x + 5

p(x) = (x - 5)(x + 1)(x - 1)

Yes, the remainder is 0 so, x-5 is a factor of p(x)

 Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

69

step-by-step explanation:

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35