The vertices of AABC are A(-6, -7), B(-3,-10) and
C(-5,2). Find the vertices of AA'B'C'. given the
translation rule below.
(x, y) (x - 2. y - 7)
a A (-8, -14), B (-5, -17), C'(-7,-5)
b
A'(-6, -12), B' (-6, -18).C'(-9, -12)
C A'(-12, -16), B(-10, -17), C'(-6, -5)
d
A'(-9, -20), B'(-6, -12). C'(-8, 8)

A, but try the rest of the points!

Step-by-step explanation:

I assume AABC means triangle ABC

Just do the operation to each point.  so A is (-6, -7)  (x - 2. y - 7) is telling you subtract 2 from -6 and 7 from -7 or in other words it changes from  (-6, -7)  to (-6 - 2. -7 - 7) = (-8, -14)

Only one answer has that point for A', but you should really really really try the rest.

a² + b²= c²

24² + 7² = c²

c= 25

4x and 6y

im not sure though