Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25 times the width of the section. Part A (2 POINTS) Create an equation to represent the area of the basketball section, A, in terms of the width, w. Part B (5 POINTS) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section? SHOW ALL WORK TO RECEIVE FULL CREDIT

A = 1.25w²

width: 14 ft; length 17.5 ft

Step-by-step explanation:

A) The length is 1.25 times the width. The width is represented by w, so the length (L) is ...

 L = 1.25w

The area (A) is the product of length and width, so is ...

 A = Lw = (1.25w)(w)

 A = 1.25w²

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B) The width of the section can be found by using the given area and solving for w:

 245 = 1.25w²

 196 = w² . . . . . . . . divide by 1.25

 14 = w . . . . . . . . . . take the square root

 L = 1.25·14 = 17.5 . . . . find the length

The dimensions of the section are 14 feet wide by 17.5 feet long.

HOPE THIS HELPS U OUT AND IF IT DID PLS MARK ME AS BRAINIEST

~ALEX

Step-by-step explanation:

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3,000,540

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