Bill is 2 years older than his brother Will. If the product of their ages is one less than five times the sum of their ages, how old are Bill and Will?

Will's age = 9 years

Bill's age = 11years

Step-by-step explanation:

Let will age = x

Bill = x +2 since he is 2 years older

x(x+2) = 5( x +x+2) - 1

Opening brackets

x² + 2x = 5(2x + 2) - 1

x² + 2x = 10x + 10 - 1

x² + 2x = 10x + 9

Collect like terms

x² + 2x - 10x - 9 = 0

x² - 8x - 9 = 0

Solve quadratically using factorisation method by finding two factors of +9 that can add up to give -8, the coefficient of x.

The factors are -9 and +1

x² + x - 9x - 9 = 0

x(x + 1) -9( x +1)

x+1) (x -9) =0

x + 1 = 0 or x -9 =0

x = -1 or 9

Age can not be negative

Therefore,

Will's age = 9 years

Bill's age = x+2 = 9+2 = 11years

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answer: x=60

  or  

sin y = 7/q

7 is the opposite side length, q is the hypotenuse

tan y = 7/r

7 is the opposite side length, r is the adjacent side length

using sohcahtoa ^^^^

cos y = adjacent/hypotenuse

cos y = r/q