What is the length of the apothem of a regular hexagon with 10-cm sides? If necessary, round to the *nearest tenth*

A) about 5.0 cm
B) about 2.9 cm
C) about 8.7 cm
D) about 9.7 cm

C

Step-by-step explanation:

10 ÷ [2 tan(180/6)]

5sqrt(3)

8.66

About 8.7cm

Apothem=8.7cm --- answer C)

Step-by-step explanation:

The regular hexagon has 6 equal sides. The hexagon consists of 6 equal equilateral triangles, of side l=10cm.

Thus, the apothem of a regular hexagon is the height in that equilateral triangle, that can be computed with:

h=l/2×sqrt(3)=10/2×1.73=5×sqrt(3)=8.66cm.

Rounding to the tenth: 8.7cm

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation: