Write as a product
c^2+d–d^2+c

(c + d)(c - d + 1)

Step-by-step explanation:

c² - d² + c + d

(c - d)(c + d) + (c + d)

(c + d)(c - d + 1)

hey

Step-by-step explanation:

c²-d²+c+d

[a²-b²=(a+b)(a-b)]

(c+d)(c-d)+c+d

take (c+d) common

(c+d)(c-d+1)

answer: no

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl