Eloise started to solve a radical equation in this way: V-2x 1 -3 = x -2x 1 -3 3 = x 3 V-2x 1 = x 3 -2x 1 -1= x 3 - 1 V-2x = x 2 (V-2x)2 = (x – 4)2 -2x = x2 - 8x 16 -2x 2x = x2 8x 16 2x 0 = x2 10x 16 0 = (x 2)(X 8) X 2 = 0 X 2 - 2 = 0 - 2 X = -2 X 8 = 0 X 8 - 8 = 0 - 8 x = -8 Both solutions are extraneous because they don't satisfy the original equation What error did it Eloise make?
A. She added 2x after squaring both sides.
B. She subtracted 1 before squaring both sides.
C. She factored x^2+10x+16 incorrectly.
D. She did not check for extraneous solutions.