Find the percent of change to the nearest tenth of a percent for centerville
Lakeside in 2000: 51,342 2010: 45,863
Centerville in 2000: 37,065 2010: 26,102
Riverview in 2000: 41,726 2010: 63,017

The percent change for centerville is 30% (rounded off to nearest tenth of a percent)

Step-by-step explanation:

Given details-

Centerville during the year 2000-37,065

Centerville during the year 2010-26,102

Per cent change to the nearest tenth of a percent

total change during the time gap of 10 years= Centerville during 2000- Centerville during 2010

⇒ total change during the time gap of 10 years=37,065-26,102

⇒ total change during the time gap of 10 years=10,963

⇒ per cent change= (total change/Centerville during 2000)*100

⇒ per cent change= (10,963/37,065)*100

⇒ 29.57776%

⇒ 30% (The answer has been rounded)

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.