The table represents the linear function f(x), and the equation represents the linear function g(x). Compare the y-intercepts and slopes of the linear functions f(x) and g(x) and choose the answer that best describes them. x f(x) 0 1 2 4 4 7 g(x) = 2x + 1

y-intercept of f(x) = 1

y-intercept of g(x) = 1

The slope of f(x) = 1.5

The slope of g(x) = 2

Step-by-step explanation:

 x   :   0    2    4

f(x) :   1     4    7

The table x , f(x) represents a linear function

The linear function has the form y = mx + c

where m is the slope and c is y-intercept

m = (y₂-y₁)/(x₂-x₁) = (7-4)/(4-2) = 3/2 = 1.5

y-intercept is the value of y at which x = 0

From the table at x = 0 ⇒y= f(x) = 1 ⇒ c = 1

∴ f(x) = 1.5x + 1

And given g(x) = 2x + 1

We will Compare the y-intercepts and slopes of the linear functions f(x) and g(x)

y-intercept of f(x) = 1

y-intercept of g(x) = 1

The slope of f(x) = 1.5

The slope of g(x) = 2

So, y-intercept of f(x) = y-intercept of g(x) = 1

And The slope of g(x) is greater than The slope of f(x)

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: