Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3206.5 g and a standard deviation of 724.6 g. Newborn females have weights with a mean of 3024.5 g and a standard deviation of 505.3 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1700 g or a female who weighs 1700 g? Since the z score for the male is zequals nothing and the z score for the female is zequals nothing, the ▼ female male has the weight that is more extreme. (Round to two decimal places.)

Since the z score for the male is z = -2.08 and the z score for the female is z = -2.62, the female has the weight that is more extreme.

Step-by-step explanation:

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Whoever's z-score has the higher absolute value has the weight that is more extreme relative to the group.

Male who weighs 1700 g

Based on sample data, newborn males have weights with a mean of 3206.5 g and a standard deviation of 724.6 g.

This means that

So

The absolute value of the zscore is 2.08

Female who weighs 1700 g

Newborn females have weights with a mean of 3024.5 g and a standard deviation of 505.3 g.

This means that

So

The absolute value of the zscore is 2.62.

So the female has the more extreme weight.

Since the z score for the male is z = -2.08 and the z score for the female is z = -2.62, the female has the weight that is more extreme.

black lol

step-by-step explanation:

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i can tell you jamal now has 3 cookies xd

tommy has 2.

this made me lol.