When an object is dropped from a building (height 16501650 feet), the object's height, h, in feet, from the ground at time, t, in seconds, after being dropped can be determined by h equals Upper P (t )equals negative 16 t squared plus 1650.h=P(t)=−16t2+1650. Find the distance an object is from the ground 33 seconds after being dropped.

1515 feet

Step-by-step explanation:

The height, h (in feet ) of the object from the ground after a given time (t) in seconds is given as:

h=P(t)=−16t²+1650

To determine the height after 3 seconds of an object being dropped, i.e. at t=3

P(t)=−16t²+1650

P(t)=−16(3)²+1650

=-16(9)+1659

=-144+1659

P(t)=1515 feet

The height of the object from the ground after 3 seconds is 1515 feet

54.864 meters

step-by-step explanation: