When someone buys a ticket for an airline flight, there is a 0.098 probability that the person will not show up for the flight. A certain jet can seat 18 passengers. Is it wise to book 20 passengers for a flight on the jet?

Determine whether or not booking 24 passengers for 22 seats on the jet is a wise decision. Select the correct choice below and fill in the answer box in that choice with the probability that there are not enough seats on the jet.

(Round to four decimal places as needed.)

A. It is a wise decision because the probability that there are not enough seats on the jet is __. So, overbooking is an unlikely event.

B. It is not a wise decision because the probability that there are not enough seats on the jet is __. So, overbooking is not an unlikely event.

C. It is not a wise decision because the probability that there are not enough seats on the jet is __. So, overbooking is an unlikely event.

D. It is a wise decision because the probability that there are not enough seats on the jet is __. So, overbooking is not an unlikely event.

Step-by-step explanation:

Probability that a person will not show up is,

P(person not show up)=0.098.

Probability that they will show up is

1-0.098=0.902

P(person will show up)=0.902

Jet passenger seat=18.

a. But is it wise to book 20 passenger seat

If the flight attendant book 20.

We want to know the probability that the two person will not show up.

The probability that the 2 person  will not show up out of the 20 is given as

Using binomial distribution

Check attachment for formulas.

P(2 not showing up) =

20C2 • 0.098² • 0.902^20=0.2319

Which is 23.19% that the 2 person  will not show up.

b. But is it wise to book 24 passengers for 22 jet seat.

The probability that the 2 will not show up out of the 24 is given as

Using binomial distribution

P(2 not showing up) =

24C2 • 0.098²• 0.902²²=0.2741

Which is 27.41% that the four person will not show up.

c. Probability of no enough seat

For 20 passengers and 18seats on jet

1-0.2319=0.7631.

For 24 passengers and 20 seats on jet

1-27.41=0.7259.

Then,  It is not a wise decision because the probability that there are not enough seats on the jet is 0.7259 (72.59%). So, overbooking is an unlikely event.

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )

answer: y=4000x+14000

step-by-step explanation: